怎么通过xml继承方式修改原模块的view的domain

Joshua

在6.0.x的OpenERP里，如果我想修改一下原模块的一个view里面的domain应该怎么实现呢？ 例如:

<br />&lt;record model=&quot;ir.actions.act_window&quot; id=&quot;crm_case_category_act_leads_all&quot;&gt;<br />&nbsp; &nbsp; &nbsp; &nbsp; &lt;field name=&quot;name&quot;&gt;Leads&lt;/field&gt;<br />&nbsp; &nbsp; &nbsp; &nbsp; &lt;field name=&quot;res_model&quot;&gt;crm.lead&lt;/field&gt;<br />&nbsp; &nbsp; &nbsp; &nbsp; &lt;field name=&quot;view_mode&quot;&gt;tree,form&lt;/field&gt;<br />&nbsp; &nbsp; &nbsp; &nbsp; &lt;field name=&quot;domain&quot;&gt;&#91;&#039;|&#039;, (&#039;type&#039;,&#039;=&#039;,&#039;lead&#039;), (&#039;type&#039;,&#039;=&#039;,False)]&lt;/field&gt;<br />&nbsp; &nbsp; &nbsp; &nbsp; &lt;field name=&quot;view_id&quot; ref=&quot;crm_case_tree_view_leads&quot;/&gt;<br />&nbsp; &nbsp; &nbsp; &nbsp; &lt;field name=&quot;search_view_id&quot; ref=&quot;crm.view_crm_case_leads_filter&quot;/&gt;<br />&nbsp; &nbsp; &nbsp; &nbsp; &lt;field name=&quot;context&quot;&gt;{&#039;search_default_current&#039;:1, &#039;default_type&#039;: &#039;lead&#039;, &#039;search_default_section_id&#039;: section_id, &#039;stage_type&#039;: &#039;lead&#039;}&lt;/field&gt;<br /><br />

我想把原来的domain改成[('type','=','lead')],但是不想通过在页面上修改xml， 欢迎集思广益 解决方案： 1.<filed name="action_id" search="[('model', '=', 'xxxxx'),('view_type', '=', 'form').....] (by.mrshelly) <field name="action_id" >abc</field> 表示在字段action_id中导入固定值abc，但如果希望搜索数据表中某个值，作为导入值，就可以用search：<filed name="action_id" search="[('model', '=', 'xxxxx'),('view_type', '=', 'form').....] 搜索符合条件的值作为action_id 的字段值 2.拷贝那个Action，重写，保持ID不变，就可以覆盖它了,Form也一样，或者继承，继承解决不了问题，拷贝下来重写，保持ID不变就OK了,在你的新模块中，老ID要加上老模块名。（by.老肖）