如何跳过父类，继承更上一级的函数？

ccdos

sale_order 的 copy

<br />&nbsp; &nbsp; def copy(self, cr, uid, id, default=None, context=None):<br />&nbsp; &nbsp; &nbsp; &nbsp; if not default:<br />&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; default = {}<br />&nbsp; &nbsp; &nbsp; &nbsp; default.update({<br />&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &#039;state&#039;: &#039;draft&#039;,<br />&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &#039;invoice_ids&#039;: &#91;],<br />&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &#039;date_confirm&#039;: False,<br />&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &#039;name&#039;: self.pool.get(&#039;ir.sequence&#039;).get(cr, uid, &#039;sale.order&#039;),<br />&nbsp; &nbsp; &nbsp; &nbsp; })<br />&nbsp; &nbsp; &nbsp; &nbsp; return super(sale_order, self).copy(cr, uid, id, default, context=context)<br /><br />

现在我需要改写 sale 的copy 方法，
准确地说，我不需要
这一行，

'name': self.pool.get('ir.sequence').get(cr, uid, 'sale.order'),

用继承的方法的话，
最后我需要
return super(sale_order, self).copy(cr, uid, id, default, context=context)

这样，事实上还是调用了上面的代码的 copy。

我该怎么做才能隔代继承？

如何跳过 父类，继承 更上一级的函数 ？

如何跳过父类，继承更上一级的函数？