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请问怎么在button 跳转 action 的时候跳到编辑页面而不是新建<button name="%(airt_product_form_fabu_action)d" string="发布页面" type="action" />这个跳转的新建页面,怎么跳到当前id的form
可以换成调用python方法,在方法里面返回action.这种方式简单.
编辑需要其action有res_id属性值,对应所编辑的id