坑过

审批流直接出发按钮事件

翻译中</em>写成了</ em>，只要是结束标签，/后面都加入了空格，导致网页编辑无法使用，解决2个小时才发现问题，记录一下。

开启重置密码功能后提示'NoneType' object has no attribute 'get' ，调试代码发现

def action_reset_password(self, cr, uid, ids, context=None):<br />&nbsp; &nbsp; &nbsp; &nbsp; &quot;&quot;&quot; create signup token for each user, and send their signup url by email &quot;&quot;&quot;<br />&nbsp; &nbsp; &nbsp; &nbsp; # prepare reset password signup<br />&nbsp; &nbsp; &nbsp; &nbsp; create_mode = bool(context.get(&#039;create_user&#039;))<br />&nbsp; &nbsp; &nbsp; &nbsp; res_partner = self.pool.get(&#039;res.partner&#039;)<br />&nbsp; &nbsp; &nbsp; &nbsp; partner_ids = [user.partner_id.id for user in self.browse(cr, uid, ids, context)]<br /><br />&nbsp; &nbsp; &nbsp; &nbsp; # no time limit for initial invitation, only for reset password<br />&nbsp; &nbsp; &nbsp; &nbsp; expiration = False if create_mode else now(days=+1)<br /><br />&nbsp; &nbsp; &nbsp; &nbsp; res_partner.signup_prepare(cr, uid, partner_ids, signup_type=&quot;reset&quot;, expiration=expiration, context=context)<br /><br />&nbsp; &nbsp; &nbsp; &nbsp; if not context:<br />&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; context = {}

context为空造成的，把这个代码放前面就可以了。

if not context:<br />&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; context = {}

调试也是B，再到A，再到原生，如果是在不同的模块中继承了同一个方法，这个又是一个什么样的效果，会不会混乱，如何避免产生混乱？

直接上代码了

class ResPartnerA(models.Model):<br />&nbsp; &nbsp; _inherit = &#039;res.partner&#039;<br /><br />&nbsp; &nbsp; @api.model<br />&nbsp; &nbsp; def im_search(self, name, limit=20):<br />&nbsp; &nbsp; &nbsp; &nbsp; return super(ResPartnerA, self).im_search(name, limit=limit)<br />class ResPartnerB(models.Model):<br />&nbsp; &nbsp; _inherit = &#039;res.partner&#039;<br /><br />&nbsp; &nbsp; @api.model<br />&nbsp; &nbsp; def im_search(self, name, limit=20):<br />&nbsp; &nbsp; &nbsp; &nbsp; return super(ResPartnerB, self).im_search(name, limit=limit)

这个继承的先后顺序谁来决定的？super指向哪个？求解释。

学习了，谢谢。